Derive Macro derive_more_impl::Product
source · #[derive(Product)]
sum
only.Expand description
§Using #[derive(Sum)]
The derived Sum
implementation will allow an iterator of your type to be
summed together into a new instance of the type with all the fields added
together. Apart from the original types requiring an implementation of Sum
, it
is also required that your type to implements Add
. So normally you want to
derive that one as well.
All this is also true for the Product
, except that then all the fields are
multiplied and an implementation of Mul
is required. This is usually the
easiest to implement by adding #[derive(MulSelf)]
.
§Example usage
#[derive(Add, Sum, PartialEq)]
struct MyInts(i32, i64);
let int_vec = vec![MyInts(2, 3), MyInts(4, 5), MyInts(6, 7)];
assert!(MyInts(12, 15) == int_vec.into_iter().sum())
§Structs
When deriving Sum
for a struct with two fields its like this:
#[derive(Add, Sum)]
struct MyInts(i32, i64);
Code like this will be generated for the Sum
implementation:
impl derive_more::Sum for MyInts {
#[inline]
fn sum<I: Iterator<Item = Self>>(iter: I) -> Self {
iter.fold(
MyInts(
derive_more::core::iter::empty::<i32>().sum(),
derive_more::core::iter::empty::<i64>().sum(),
),
derive_more::core::ops::Add::add,
)
}
}
The trick here is that we get the identity struct by calling sum on empty
iterators.
This way we can get the identity for sum (i.e. 0
) and the identity for product
(i.e. 1
).
§Enums
Deriving Sum
for enums is not supported.