sqruff_lib/rules/capitalisation/
cp03.rsuse ahash::AHashMap;
use regex::Regex;
use sqruff_lib_core::dialects::syntax::{SyntaxKind, SyntaxSet};
use super::cp01::RuleCP01;
use crate::core::config::Value;
use crate::core::rules::base::{Erased, ErasedRule, LintResult, Rule, RuleGroups};
use crate::core::rules::context::RuleContext;
use crate::core::rules::crawlers::{Crawler, SegmentSeekerCrawler};
#[derive(Debug, Clone)]
pub struct RuleCP03 {
base: RuleCP01,
}
impl Default for RuleCP03 {
fn default() -> Self {
Self {
base: RuleCP01 {
skip_literals: false,
exclude_parent_types: &[],
..Default::default()
},
}
}
}
impl Rule for RuleCP03 {
fn load_from_config(&self, config: &AHashMap<String, Value>) -> Result<ErasedRule, String> {
Ok(RuleCP03 {
base: RuleCP01 {
capitalisation_policy: config["extended_capitalisation_policy"]
.as_string()
.unwrap()
.into(),
description_elem: "Function names",
ignore_words: config["ignore_words"]
.map(|it| {
it.as_array()
.unwrap()
.iter()
.map(|it| it.as_string().unwrap().to_lowercase())
.collect()
})
.unwrap_or_default(),
ignore_words_regex: config["ignore_words_regex"]
.map(|it| {
it.as_array()
.unwrap()
.iter()
.map(|it| Regex::new(it.as_string().unwrap()).unwrap())
.collect()
})
.unwrap_or_default(),
..Default::default()
},
}
.erased())
}
fn name(&self) -> &'static str {
"capitalisation.functions"
}
fn description(&self) -> &'static str {
"Inconsistent capitalisation of function names."
}
fn long_description(&self) -> &'static str {
r#"
**Anti-pattern**
In this example, the two `SUM` functions don’t have the same capitalisation.
```sql
SELECT
sum(a) AS aa,
SUM(b) AS bb
FROM foo
```
**Best practice**
Make the case consistent.
```sql
SELECT
sum(a) AS aa,
sum(b) AS bb
FROM foo
```
"#
}
fn groups(&self) -> &'static [RuleGroups] {
&[
RuleGroups::All,
RuleGroups::Core,
RuleGroups::Capitalisation,
]
}
fn eval(&self, context: RuleContext) -> Vec<LintResult> {
self.base.eval(context)
}
fn is_fix_compatible(&self) -> bool {
true
}
fn crawl_behaviour(&self) -> Crawler {
SegmentSeekerCrawler::new(const {SyntaxSet::new(&[
SyntaxKind::FunctionNameIdentifier,
SyntaxKind::BareFunction,
]) })
.into()
}
}