Function wasmtime_environ::__core::intrinsics::is_val_statically_known
const: unstable · source · pub fn is_val_statically_known<T>(_arg: T) -> boolwhere
T: Copy,
core_intrinsics
)Expand description
Returns whether the argument’s value is statically known at compile-time.
This is useful when there is a way of writing the code that will
be faster when some variables have known values, but slower
in the general case: an if is_val_statically_known(var)
can be used
to select between these two variants. The if
will be optimized away
and only the desired branch remains.
Formally speaking, this function non-deterministically returns true
or false
, and the caller has to ensure sound behavior for both cases.
In other words, the following code has Undefined Behavior:
#![feature(is_val_statically_known)]
#![feature(core_intrinsics)]
use std::hint::unreachable_unchecked;
use std::intrinsics::is_val_statically_known;
if !is_val_statically_known(0) { unsafe { unreachable_unchecked(); } }
This also means that the following code’s behavior is unspecified; it may panic, or it may not:
#![feature(is_val_statically_known)]
#![feature(core_intrinsics)]
use std::intrinsics::is_val_statically_known;
assert_eq!(is_val_statically_known(0), is_val_statically_known(0));
Unsafe code may not rely on is_val_statically_known
returning any
particular value, ever. However, the compiler will generally make it
return true
only if the value of the argument is actually known.
When calling this in a const fn
, both paths must be semantically
equivalent, that is, the result of the true
branch and the false
branch must return the same value and have the same side-effects no
matter what.