1.36.0[−][src]Union scale_info::prelude::mem::MaybeUninit
A wrapper type to construct uninitialized instances of T
.
Initialization invariant
The compiler, in general, assumes that a variable is properly initialized according to the requirements of the variable's type. For example, a variable of reference type must be aligned and non-NULL. This is an invariant that must always be upheld, even in unsafe code. As a consequence, zero-initializing a variable of reference type causes instantaneous undefined behavior, no matter whether that reference ever gets used to access memory:
use std::mem::{self, MaybeUninit}; let x: &i32 = unsafe { mem::zeroed() }; // undefined behavior! ⚠️ // The equivalent code with `MaybeUninit<&i32>`: let x: &i32 = unsafe { MaybeUninit::zeroed().assume_init() }; // undefined behavior! ⚠️
This is exploited by the compiler for various optimizations, such as eliding
run-time checks and optimizing enum
layout.
Similarly, entirely uninitialized memory may have any content, while a bool
must
always be true
or false
. Hence, creating an uninitialized bool
is undefined behavior:
use std::mem::{self, MaybeUninit}; let b: bool = unsafe { mem::uninitialized() }; // undefined behavior! ⚠️ // The equivalent code with `MaybeUninit<bool>`: let b: bool = unsafe { MaybeUninit::uninit().assume_init() }; // undefined behavior! ⚠️
Moreover, uninitialized memory is special in that the compiler knows that it does not have a fixed value. This makes it undefined behavior to have uninitialized data in a variable even if that variable has an integer type, which otherwise can hold any fixed bit pattern:
use std::mem::{self, MaybeUninit}; let x: i32 = unsafe { mem::uninitialized() }; // undefined behavior! ⚠️ // The equivalent code with `MaybeUninit<i32>`: let x: i32 = unsafe { MaybeUninit::uninit().assume_init() }; // undefined behavior! ⚠️
(Notice that the rules around uninitialized integers are not finalized yet, but until they are, it is advisable to avoid them.)
On top of that, remember that most types have additional invariants beyond merely
being considered initialized at the type level. For example, a 1
-initialized Vec<T>
is considered initialized (under the current implementation; this does not constitute
a stable guarantee) because the only requirement the compiler knows about it
is that the data pointer must be non-null. Creating such a Vec<T>
does not cause
immediate undefined behavior, but will cause undefined behavior with most
safe operations (including dropping it).
Examples
MaybeUninit<T>
serves to enable unsafe code to deal with uninitialized data.
It is a signal to the compiler indicating that the data here might not
be initialized:
use std::mem::MaybeUninit; // Create an explicitly uninitialized reference. The compiler knows that data inside // a `MaybeUninit<T>` may be invalid, and hence this is not UB: let mut x = MaybeUninit::<&i32>::uninit(); // Set it to a valid value. unsafe { x.as_mut_ptr().write(&0); } // Extract the initialized data -- this is only allowed *after* properly // initializing `x`! let x = unsafe { x.assume_init() };
The compiler then knows to not make any incorrect assumptions or optimizations on this code.
You can think of MaybeUninit<T>
as being a bit like Option<T>
but without
any of the run-time tracking and without any of the safety checks.
out-pointers
You can use MaybeUninit<T>
to implement "out-pointers": instead of returning data
from a function, pass it a pointer to some (uninitialized) memory to put the
result into. This can be useful when it is important for the caller to control
how the memory the result is stored in gets allocated, and you want to avoid
unnecessary moves.
use std::mem::MaybeUninit; unsafe fn make_vec(out: *mut Vec<i32>) { // `write` does not drop the old contents, which is important. out.write(vec![1, 2, 3]); } let mut v = MaybeUninit::uninit(); unsafe { make_vec(v.as_mut_ptr()); } // Now we know `v` is initialized! This also makes sure the vector gets // properly dropped. let v = unsafe { v.assume_init() }; assert_eq!(&v, &[1, 2, 3]);
Initializing an array element-by-element
MaybeUninit<T>
can be used to initialize a large array element-by-element:
use std::mem::{self, MaybeUninit}; let data = { // Create an uninitialized array of `MaybeUninit`. The `assume_init` is // safe because the type we are claiming to have initialized here is a // bunch of `MaybeUninit`s, which do not require initialization. let mut data: [MaybeUninit<Vec<u32>>; 1000] = unsafe { MaybeUninit::uninit().assume_init() }; // Dropping a `MaybeUninit` does nothing. Thus using raw pointer // assignment instead of `ptr::write` does not cause the old // uninitialized value to be dropped. Also if there is a panic during // this loop, we have a memory leak, but there is no memory safety // issue. for elem in &mut data[..] { *elem = MaybeUninit::new(vec![42]); } // Everything is initialized. Transmute the array to the // initialized type. unsafe { mem::transmute::<_, [Vec<u32>; 1000]>(data) } }; assert_eq!(&data[0], &[42]);
You can also work with partially initialized arrays, which could be found in low-level datastructures.
use std::mem::MaybeUninit; use std::ptr; // Create an uninitialized array of `MaybeUninit`. The `assume_init` is // safe because the type we are claiming to have initialized here is a // bunch of `MaybeUninit`s, which do not require initialization. let mut data: [MaybeUninit<String>; 1000] = unsafe { MaybeUninit::uninit().assume_init() }; // Count the number of elements we have assigned. let mut data_len: usize = 0; for elem in &mut data[0..500] { *elem = MaybeUninit::new(String::from("hello")); data_len += 1; } // For each item in the array, drop if we allocated it. for elem in &mut data[0..data_len] { unsafe { ptr::drop_in_place(elem.as_mut_ptr()); } }
Initializing a struct field-by-field
There is currently no supported way to create a raw pointer or reference
to a field of a struct inside MaybeUninit<Struct>
. That means it is not possible
to create a struct by calling MaybeUninit::uninit::<Struct>()
and then writing
to its fields.
Layout
MaybeUninit<T>
is guaranteed to have the same size, alignment, and ABI as T
:
use std::mem::{MaybeUninit, size_of, align_of}; assert_eq!(size_of::<MaybeUninit<u64>>(), size_of::<u64>()); assert_eq!(align_of::<MaybeUninit<u64>>(), align_of::<u64>());
However remember that a type containing a MaybeUninit<T>
is not necessarily the same
layout; Rust does not in general guarantee that the fields of a Foo<T>
have the same order as
a Foo<U>
even if T
and U
have the same size and alignment. Furthermore because any bit
value is valid for a MaybeUninit<T>
the compiler can't apply non-zero/niche-filling
optimizations, potentially resulting in a larger size:
assert_eq!(size_of::<Option<bool>>(), 1); assert_eq!(size_of::<Option<MaybeUninit<bool>>>(), 2);
If T
is FFI-safe, then so is MaybeUninit<T>
.
While MaybeUninit
is #[repr(transparent)]
(indicating it guarantees the same size,
alignment, and ABI as T
), this does not change any of the previous caveats. Option<T>
and
Option<MaybeUninit<T>>
may still have different sizes, and types containing a field of type
T
may be laid out (and sized) differently than if that field were MaybeUninit<T>
.
MaybeUninit
is a union type, and #[repr(transparent)]
on unions is unstable (see the
tracking issue). Over time, the exact
guarantees of #[repr(transparent)]
on unions may evolve, and MaybeUninit
may or may not
remain #[repr(transparent)]
. That said, MaybeUninit<T>
will always guarantee that it has
the same size, alignment, and ABI as T
; it's just that the way MaybeUninit
implements that
guarantee may evolve.
Implementations
impl<T> MaybeUninit<T>
[src]
pub const fn new(val: T) -> MaybeUninit<T>
1.36.0 (const: 1.36.0)[src]
Creates a new MaybeUninit<T>
initialized with the given value.
It is safe to call assume_init
on the return value of this function.
Note that dropping a MaybeUninit<T>
will never call T
's drop code.
It is your responsibility to make sure T
gets dropped if it got initialized.
Example
use std::mem::MaybeUninit; let v: MaybeUninit<Vec<u8>> = MaybeUninit::new(vec![42]);
pub const fn uninit() -> MaybeUninit<T>
1.36.0 (const: 1.36.0)[src]
Creates a new MaybeUninit<T>
in an uninitialized state.
Note that dropping a MaybeUninit<T>
will never call T
's drop code.
It is your responsibility to make sure T
gets dropped if it got initialized.
See the type-level documentation for some examples.
Example
use std::mem::MaybeUninit; let v: MaybeUninit<String> = MaybeUninit::uninit();
pub const fn uninit_array<const LEN: usize>() -> [MaybeUninit<T>; LEN]
[src]
maybe_uninit_uninit_array
)Create a new array of MaybeUninit<T>
items, in an uninitialized state.
Note: in a future Rust version this method may become unnecessary
when array literal syntax allows
repeating const expressions.
The example below could then use let mut buf = [MaybeUninit::<u8>::uninit(); 32];
.
Examples
#![feature(maybe_uninit_uninit_array, maybe_uninit_extra, maybe_uninit_slice)] use std::mem::MaybeUninit; extern "C" { fn read_into_buffer(ptr: *mut u8, max_len: usize) -> usize; } /// Returns a (possibly smaller) slice of data that was actually read fn read(buf: &mut [MaybeUninit<u8>]) -> &[u8] { unsafe { let len = read_into_buffer(buf.as_mut_ptr() as *mut u8, buf.len()); MaybeUninit::slice_assume_init_ref(&buf[..len]) } } let mut buf: [MaybeUninit<u8>; 32] = MaybeUninit::uninit_array(); let data = read(&mut buf);
pub fn zeroed() -> MaybeUninit<T>
[src]
Creates a new MaybeUninit<T>
in an uninitialized state, with the memory being
filled with 0
bytes. It depends on T
whether that already makes for
proper initialization. For example, MaybeUninit<usize>::zeroed()
is initialized,
but MaybeUninit<&'static i32>::zeroed()
is not because references must not
be null.
Note that dropping a MaybeUninit<T>
will never call T
's drop code.
It is your responsibility to make sure T
gets dropped if it got initialized.
Example
Correct usage of this function: initializing a struct with zero, where all fields of the struct can hold the bit-pattern 0 as a valid value.
use std::mem::MaybeUninit; let x = MaybeUninit::<(u8, bool)>::zeroed(); let x = unsafe { x.assume_init() }; assert_eq!(x, (0, false));
Incorrect usage of this function: calling x.zeroed().assume_init()
when 0
is not a valid bit-pattern for the type:
use std::mem::MaybeUninit; enum NotZero { One = 1, Two = 2 } let x = MaybeUninit::<(u8, NotZero)>::zeroed(); let x = unsafe { x.assume_init() }; // Inside a pair, we create a `NotZero` that does not have a valid discriminant. // This is undefined behavior. ⚠️
pub const fn write(&mut self, val: T) -> &mut T
[src]
maybe_uninit_extra
)Sets the value of the MaybeUninit<T>
. This overwrites any previous value
without dropping it, so be careful not to use this twice unless you want to
skip running the destructor. For your convenience, this also returns a mutable
reference to the (now safely initialized) contents of self
.
pub const fn as_ptr(&self) -> *const T
[src]
Gets a pointer to the contained value. Reading from this pointer or turning it
into a reference is undefined behavior unless the MaybeUninit<T>
is initialized.
Writing to memory that this pointer (non-transitively) points to is undefined behavior
(except inside an UnsafeCell<T>
).
Examples
Correct usage of this method:
use std::mem::MaybeUninit; let mut x = MaybeUninit::<Vec<u32>>::uninit(); unsafe { x.as_mut_ptr().write(vec![0, 1, 2]); } // Create a reference into the `MaybeUninit<T>`. This is okay because we initialized it. let x_vec = unsafe { &*x.as_ptr() }; assert_eq!(x_vec.len(), 3);
Incorrect usage of this method:
use std::mem::MaybeUninit; let x = MaybeUninit::<Vec<u32>>::uninit(); let x_vec = unsafe { &*x.as_ptr() }; // We have created a reference to an uninitialized vector! This is undefined behavior. ⚠️
(Notice that the rules around references to uninitialized data are not finalized yet, but until they are, it is advisable to avoid them.)
pub const fn as_mut_ptr(&mut self) -> *mut T
[src]
Gets a mutable pointer to the contained value. Reading from this pointer or turning it
into a reference is undefined behavior unless the MaybeUninit<T>
is initialized.
Examples
Correct usage of this method:
use std::mem::MaybeUninit; let mut x = MaybeUninit::<Vec<u32>>::uninit(); unsafe { x.as_mut_ptr().write(vec![0, 1, 2]); } // Create a reference into the `MaybeUninit<Vec<u32>>`. // This is okay because we initialized it. let x_vec = unsafe { &mut *x.as_mut_ptr() }; x_vec.push(3); assert_eq!(x_vec.len(), 4);
Incorrect usage of this method:
use std::mem::MaybeUninit; let mut x = MaybeUninit::<Vec<u32>>::uninit(); let x_vec = unsafe { &mut *x.as_mut_ptr() }; // We have created a reference to an uninitialized vector! This is undefined behavior. ⚠️
(Notice that the rules around references to uninitialized data are not finalized yet, but until they are, it is advisable to avoid them.)
pub const unsafe fn assume_init(self) -> T
[src]
Extracts the value from the MaybeUninit<T>
container. This is a great way
to ensure that the data will get dropped, because the resulting T
is
subject to the usual drop handling.
Safety
It is up to the caller to guarantee that the MaybeUninit<T>
really is in an initialized
state. Calling this when the content is not yet fully initialized causes immediate undefined
behavior. The type-level documentation contains more information about
this initialization invariant.
On top of that, remember that most types have additional invariants beyond merely
being considered initialized at the type level. For example, a 1
-initialized Vec<T>
is considered initialized (under the current implementation; this does not constitute
a stable guarantee) because the only requirement the compiler knows about it
is that the data pointer must be non-null. Creating such a Vec<T>
does not cause
immediate undefined behavior, but will cause undefined behavior with most
safe operations (including dropping it).
Examples
Correct usage of this method:
use std::mem::MaybeUninit; let mut x = MaybeUninit::<bool>::uninit(); unsafe { x.as_mut_ptr().write(true); } let x_init = unsafe { x.assume_init() }; assert_eq!(x_init, true);
Incorrect usage of this method:
use std::mem::MaybeUninit; let x = MaybeUninit::<Vec<u32>>::uninit(); let x_init = unsafe { x.assume_init() }; // `x` had not been initialized yet, so this last line caused undefined behavior. ⚠️
pub const unsafe fn assume_init_read(&self) -> T
[src]
maybe_uninit_extra
)Reads the value from the MaybeUninit<T>
container. The resulting T
is subject
to the usual drop handling.
Whenever possible, it is preferable to use assume_init
instead, which
prevents duplicating the content of the MaybeUninit<T>
.
Safety
It is up to the caller to guarantee that the MaybeUninit<T>
really is in an initialized
state. Calling this when the content is not yet fully initialized causes undefined
behavior. The type-level documentation contains more information about
this initialization invariant.
Moreover, this leaves a copy of the same data behind in the MaybeUninit<T>
. When using
multiple copies of the data (by calling assume_init_read
multiple times, or first
calling assume_init_read
and then assume_init
), it is your responsibility
to ensure that that data may indeed be duplicated.
Examples
Correct usage of this method:
#![feature(maybe_uninit_extra)] use std::mem::MaybeUninit; let mut x = MaybeUninit::<u32>::uninit(); x.write(13); let x1 = unsafe { x.assume_init_read() }; // `u32` is `Copy`, so we may read multiple times. let x2 = unsafe { x.assume_init_read() }; assert_eq!(x1, x2); let mut x = MaybeUninit::<Option<Vec<u32>>>::uninit(); x.write(None); let x1 = unsafe { x.assume_init_read() }; // Duplicating a `None` value is okay, so we may read multiple times. let x2 = unsafe { x.assume_init_read() }; assert_eq!(x1, x2);
Incorrect usage of this method:
#![feature(maybe_uninit_extra)] use std::mem::MaybeUninit; let mut x = MaybeUninit::<Option<Vec<u32>>>::uninit(); x.write(Some(vec![0, 1, 2])); let x1 = unsafe { x.assume_init_read() }; let x2 = unsafe { x.assume_init_read() }; // We now created two copies of the same vector, leading to a double-free ⚠️ when // they both get dropped!
pub unsafe fn assume_init_drop(&mut self)
[src]
maybe_uninit_extra
)Drops the contained value in place.
If you have ownership of the MaybeUninit
, you can use assume_init
instead.
Safety
It is up to the caller to guarantee that the MaybeUninit<T>
really is
in an initialized state. Calling this when the content is not yet fully
initialized causes undefined behavior.
On top of that, all additional invariants of the type T
must be
satisfied, as the Drop
implementation of T
(or its members) may
rely on this. For example, a 1
-initialized Vec<T>
is considered
initialized (under the current implementation; this does not constitute
a stable guarantee) because the only requirement the compiler knows
about it is that the data pointer must be non-null. Dropping such a
Vec<T>
however will cause undefined behaviour.
pub const unsafe fn assume_init_ref(&self) -> &T
[src]
maybe_uninit_ref
)Gets a shared reference to the contained value.
This can be useful when we want to access a MaybeUninit
that has been
initialized but don't have ownership of the MaybeUninit
(preventing the use
of .assume_init()
).
Safety
Calling this when the content is not yet fully initialized causes undefined
behavior: it is up to the caller to guarantee that the MaybeUninit<T>
really
is in an initialized state.
Examples
Correct usage of this method:
#![feature(maybe_uninit_ref)] use std::mem::MaybeUninit; let mut x = MaybeUninit::<Vec<u32>>::uninit(); // Initialize `x`: unsafe { x.as_mut_ptr().write(vec![1, 2, 3]); } // Now that our `MaybeUninit<_>` is known to be initialized, it is okay to // create a shared reference to it: let x: &Vec<u32> = unsafe { // SAFETY: `x` has been initialized. x.assume_init_ref() }; assert_eq!(x, &vec![1, 2, 3]);
Incorrect usages of this method:
#![feature(maybe_uninit_ref)] use std::mem::MaybeUninit; let x = MaybeUninit::<Vec<u32>>::uninit(); let x_vec: &Vec<u32> = unsafe { x.assume_init_ref() }; // We have created a reference to an uninitialized vector! This is undefined behavior. ⚠️
#![feature(maybe_uninit_ref)] use std::{cell::Cell, mem::MaybeUninit}; let b = MaybeUninit::<Cell<bool>>::uninit(); // Initialize the `MaybeUninit` using `Cell::set`: unsafe { b.assume_init_ref().set(true); // ^^^^^^^^^^^^^^^ // Reference to an uninitialized `Cell<bool>`: UB! }
pub const unsafe fn assume_init_mut(&mut self) -> &mut T
[src]
maybe_uninit_ref
)Gets a mutable (unique) reference to the contained value.
This can be useful when we want to access a MaybeUninit
that has been
initialized but don't have ownership of the MaybeUninit
(preventing the use
of .assume_init()
).
Safety
Calling this when the content is not yet fully initialized causes undefined
behavior: it is up to the caller to guarantee that the MaybeUninit<T>
really
is in an initialized state. For instance, .assume_init_mut()
cannot be used to
initialize a MaybeUninit
.
Examples
Correct usage of this method:
#![feature(maybe_uninit_ref)] use std::mem::MaybeUninit; extern "C" { /// Initializes *all* the bytes of the input buffer. fn initialize_buffer(buf: *mut [u8; 2048]); } let mut buf = MaybeUninit::<[u8; 2048]>::uninit(); // Initialize `buf`: unsafe { initialize_buffer(buf.as_mut_ptr()); } // Now we know that `buf` has been initialized, so we could `.assume_init()` it. // However, using `.assume_init()` may trigger a `memcpy` of the 2048 bytes. // To assert our buffer has been initialized without copying it, we upgrade // the `&mut MaybeUninit<[u8; 2048]>` to a `&mut [u8; 2048]`: let buf: &mut [u8; 2048] = unsafe { // SAFETY: `buf` has been initialized. buf.assume_init_mut() }; // Now we can use `buf` as a normal slice: buf.sort_unstable(); assert!( buf.windows(2).all(|pair| pair[0] <= pair[1]), "buffer is sorted", );
Incorrect usages of this method:
You cannot use .assume_init_mut()
to initialize a value:
#![feature(maybe_uninit_ref)] use std::mem::MaybeUninit; let mut b = MaybeUninit::<bool>::uninit(); unsafe { *b.assume_init_mut() = true; // We have created a (mutable) reference to an uninitialized `bool`! // This is undefined behavior. ⚠️ }
For instance, you cannot Read
into an uninitialized buffer:
#![feature(maybe_uninit_ref)] use std::{io, mem::MaybeUninit}; fn read_chunk (reader: &'_ mut dyn io::Read) -> io::Result<[u8; 64]> { let mut buffer = MaybeUninit::<[u8; 64]>::uninit(); reader.read_exact(unsafe { buffer.assume_init_mut() })?; // ^^^^^^^^^^^^^^^^^^^^^^^^ // (mutable) reference to uninitialized memory! // This is undefined behavior. Ok(unsafe { buffer.assume_init() }) }
Nor can you use direct field access to do field-by-field gradual initialization:
#![feature(maybe_uninit_ref)] use std::{mem::MaybeUninit, ptr}; struct Foo { a: u32, b: u8, } let foo: Foo = unsafe { let mut foo = MaybeUninit::<Foo>::uninit(); ptr::write(&mut foo.assume_init_mut().a as *mut u32, 1337); // ^^^^^^^^^^^^^^^^^^^^^ // (mutable) reference to uninitialized memory! // This is undefined behavior. ptr::write(&mut foo.assume_init_mut().b as *mut u8, 42); // ^^^^^^^^^^^^^^^^^^^^^ // (mutable) reference to uninitialized memory! // This is undefined behavior. foo.assume_init() };
pub unsafe fn array_assume_init<const N: usize>(
array: [MaybeUninit<T>; N]
) -> [T; N]
[src]
array: [MaybeUninit<T>; N]
) -> [T; N]
maybe_uninit_array_assume_init
)Extracts the values from an array of MaybeUninit
containers.
Safety
It is up to the caller to guarantee that all elements of the array are in an initialized state.
Examples
#![feature(maybe_uninit_uninit_array)] #![feature(maybe_uninit_array_assume_init)] use std::mem::MaybeUninit; let mut array: [MaybeUninit<i32>; 3] = MaybeUninit::uninit_array(); array[0] = MaybeUninit::new(0); array[1] = MaybeUninit::new(1); array[2] = MaybeUninit::new(2); // SAFETY: Now safe as we initialised all elements let array = unsafe { MaybeUninit::array_assume_init(array) }; assert_eq!(array, [0, 1, 2]);
pub const unsafe fn slice_assume_init_ref(slice: &[MaybeUninit<T>]) -> &[T]ⓘ
[src]
maybe_uninit_slice
)Assuming all the elements are initialized, get a slice to them.
Safety
It is up to the caller to guarantee that the MaybeUninit<T>
elements
really are in an initialized state.
Calling this when the content is not yet fully initialized causes undefined behavior.
See assume_init_ref
for more details and examples.
pub const unsafe fn slice_assume_init_mut(
slice: &mut [MaybeUninit<T>]
) -> &mut [T]ⓘ
[src]
slice: &mut [MaybeUninit<T>]
) -> &mut [T]ⓘ
maybe_uninit_slice
)Assuming all the elements are initialized, get a mutable slice to them.
Safety
It is up to the caller to guarantee that the MaybeUninit<T>
elements
really are in an initialized state.
Calling this when the content is not yet fully initialized causes undefined behavior.
See assume_init_mut
for more details and examples.
pub const fn slice_as_ptr(this: &[MaybeUninit<T>]) -> *const T
[src]
maybe_uninit_slice
)Gets a pointer to the first element of the array.
pub const fn slice_as_mut_ptr(this: &mut [MaybeUninit<T>]) -> *mut T
[src]
maybe_uninit_slice
)Gets a mutable pointer to the first element of the array.
pub fn write_slice(this: &'a mut [MaybeUninit<T>], src: &[T]) -> &'a mut [T]ⓘ where
T: Copy,
[src]
T: Copy,
maybe_uninit_write_slice
)Copies the elements from src
to this
, returning a mutable reference to the now initalized contents of this
.
If T
does not implement Copy
, use write_slice_cloned
This is similar to slice::copy_from_slice
.
Panics
This function will panic if the two slices have different lengths.
Examples
#![feature(maybe_uninit_write_slice)] use std::mem::MaybeUninit; let mut dst = [MaybeUninit::uninit(); 32]; let src = [0; 32]; let init = MaybeUninit::write_slice(&mut dst, &src); assert_eq!(init, src);
#![feature(maybe_uninit_write_slice, vec_spare_capacity)] use std::mem::MaybeUninit; let mut vec = Vec::with_capacity(32); let src = [0; 16]; MaybeUninit::write_slice(&mut vec.spare_capacity_mut()[..src.len()], &src); // SAFETY: we have just copied all the elements of len into the spare capacity // the first src.len() elements of the vec are valid now. unsafe { vec.set_len(src.len()); } assert_eq!(vec, src);
pub fn write_slice_cloned(
this: &'a mut [MaybeUninit<T>],
src: &[T]
) -> &'a mut [T]ⓘ where
T: Clone,
[src]
this: &'a mut [MaybeUninit<T>],
src: &[T]
) -> &'a mut [T]ⓘ where
T: Clone,
maybe_uninit_write_slice
)Clones the elements from src
to this
, returning a mutable reference to the now initalized contents of this
.
Any already initalized elements will not be dropped.
If T
implements Copy
, use write_slice
This is similar to slice::clone_from_slice
but does not drop existing elements.
Panics
This function will panic if the two slices have different lengths, or if the implementation of Clone
panics.
If there is a panic, the already cloned elements will be dropped.
Examples
#![feature(maybe_uninit_write_slice)] use std::mem::MaybeUninit; let mut dst = [MaybeUninit::uninit(), MaybeUninit::uninit(), MaybeUninit::uninit(), MaybeUninit::uninit(), MaybeUninit::uninit()]; let src = ["wibbly".to_string(), "wobbly".to_string(), "timey".to_string(), "wimey".to_string(), "stuff".to_string()]; let init = MaybeUninit::write_slice_cloned(&mut dst, &src); assert_eq!(init, src);
#![feature(maybe_uninit_write_slice, vec_spare_capacity)] use std::mem::MaybeUninit; let mut vec = Vec::with_capacity(32); let src = ["rust", "is", "a", "pretty", "cool", "language"]; MaybeUninit::write_slice_cloned(&mut vec.spare_capacity_mut()[..src.len()], &src); // SAFETY: we have just cloned all the elements of len into the spare capacity // the first src.len() elements of the vec are valid now. unsafe { vec.set_len(src.len()); } assert_eq!(vec, src);
Trait Implementations
impl<T> Clone for MaybeUninit<T> where
T: Copy,
[src]
T: Copy,
pub fn clone(&self) -> MaybeUninit<T>
[src]
pub fn clone_from(&mut self, source: &Self)
1.0.0[src]
impl<T> Copy for MaybeUninit<T> where
T: Copy,
[src]
T: Copy,
impl<T> Debug for MaybeUninit<T>
1.41.0[src]
Auto Trait Implementations
impl<T> RefUnwindSafe for MaybeUninit<T> where
T: RefUnwindSafe,
[src]
T: RefUnwindSafe,
impl<T> Send for MaybeUninit<T> where
T: Send,
[src]
T: Send,
impl<T> Sync for MaybeUninit<T> where
T: Sync,
[src]
T: Sync,
impl<T> Unpin for MaybeUninit<T> where
T: Unpin,
[src]
T: Unpin,
impl<T> UnwindSafe for MaybeUninit<T> where
T: UnwindSafe,
[src]
T: UnwindSafe,
Blanket Implementations
impl<T> Any for T where
T: 'static + ?Sized,
[src]
T: 'static + ?Sized,
impl<T> Borrow<T> for T where
T: ?Sized,
[src]
T: ?Sized,
impl<T> BorrowMut<T> for T where
T: ?Sized,
[src]
T: ?Sized,
pub fn borrow_mut(&mut self) -> &mut T
[src]
impl<T> From<T> for T
[src]
impl<T, U> Into<U> for T where
U: From<T>,
[src]
U: From<T>,
impl<T> ToOwned for T where
T: Clone,
[src]
T: Clone,
type Owned = T
The resulting type after obtaining ownership.
pub fn to_owned(&self) -> T
[src]
pub fn clone_into(&self, target: &mut T)
[src]
impl<T, U> TryFrom<U> for T where
U: Into<T>,
[src]
U: Into<T>,
type Error = Infallible
The type returned in the event of a conversion error.
pub fn try_from(value: U) -> Result<T, <T as TryFrom<U>>::Error>
[src]
impl<T, U> TryInto<U> for T where
U: TryFrom<T>,
[src]
U: TryFrom<T>,